A object of mass 50kg is placed on a horizontal floor with a smooth surface. If the velocity of the object changes from stationary to 25.0 m/s in 5 seconds when is acted by a force, find the magnitude of the force that is acting?

**Answer: **

We know that we can find the magnitude of a force by using the formula F = ma. The mass m is already given in the question, but the acceleration is not give directly.

We can determine the acceleration from the formula

\begin{gathered}
a = \frac{{v - u}}
{t} \hfill \\
a = \frac{{25 - 0}}
{5} = 5ms^{ - 2} \hfill \\
\end{gathered}

From the formula

F = ma = (50)(5) = 250N

The force acting on the box is 250N.